05 August 2008
Implement the following operations of a queue using stacks.
Example:
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MyQueue queue = new MyQueue();
queue.push(1);
queue.push(2);
queue.peek(); // returns 1
queue.pop(); // returns 1
queue.empty(); // returns false
Notes:
1
push to top
, 1
peek/pop from top
, 1
size
, and 1
is empty
operations are valid.用栈来实现队列,刚好和225-Implement Stack using Queues相反。这个现实主要是用在读写分离的情况下,函数式编程里面也常实现。
栈和队列的核心不同点就是栈是先进后出,而队列是先进先出,所以要用栈的先进后出的特性来模拟出队列的先进先出。那么怎么做呢,只要我们在插入元素的时候每次都从前面插入即可,比如如果一个队列是1,2,3,4,那么在栈中保存为4,3,2,1,那么返回栈顶元素1,也就是队列的首元素,则问题迎刃而解。所以此题的难度是push函数,我们需要一个辅助栈s2,把s的元素也逆着顺序存入temp中,此时加入新元素x,再把temp中的元素存回来,这样就是我们要的顺序了,其他三个操作也就直接调用栈的操作即可。
把逻辑都写在push里面
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class MyQueue {
Stack<Integer> queue = new Stack<>();
/** Initialize your data structure here. */
public MyQueue() {
}
/** Push element x to the back of queue. */
public void push(int x) {
Stack<Integer> temp = new Stack<Integer>();
while(!queue.empty()){
temp.push(queue.pop());
}
queue.push(x);
while(!temp.empty()){
queue.push(temp.pop());
}
}
/** Removes the element from in front of queue and returns that element. */
public int pop() {
return queue.pop();
}
/** Get the front element. */
public int peek() {
return queue.peek();
}
/** Returns whether the queue is empty. */
public boolean empty() {
return queue.empty();
}
}
/**
* Your MyQueue object will be instantiated and called as such:
* MyQueue obj = new MyQueue();
* obj.push(x);
* int param_2 = obj.pop();
* int param_3 = obj.peek();
* boolean param_4 = obj.empty();
*/
上面那个解法简单容易理解,但是效率不高,因为每次在push的时候,都要翻转两边栈,下面这个方法使用了两个栈s1和s2,其中新进栈的都先缓存在s1中,当要pop和peek的时候,才将s1中所有元素移到s2中操作,这样可以得到优化。
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class MyQueue {
Stack<Integer> s1 = new Stack<>();
Stack<Integer> s2 = new Stack<>();
/** Initialize your data structure here. */
public MyQueue() {
}
/** Push element x to the back of queue. */
public void push(int x) {
s1.push(x);
}
/** Removes the element from in front of queue and returns that element. */
public int pop() {
peek();
return s2.pop();
}
/** Get the front element. */
public int peek() {
if (s2.isEmpty()) {
while (!s1.isEmpty()) {
s2.push(s1.pop());
}
}
return s2.peek();
}
/** Returns whether the queue is empty. */
public boolean empty() {
return s1.isEmpty() && s2.isEmpty();
}
}
/**
* Your MyQueue object will be instantiated and called as such:
* MyQueue obj = new MyQueue();
* obj.push(x);
* int param_2 = obj.pop();
* int param_3 = obj.peek();
* boolean param_4 = obj.empty();
*/
直接调用原生stack的方法,遇到push就把元素从s2往s1倒,遇到pop和peek就把元素从s1往s2倒
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class MyQueue {
Stack<Integer> s1;
Stack<Integer> s2;
/** Initialize your data structure here. */
public MyQueue() {
s1 = new Stack<>();
s2 = new Stack<>();
}
/** Push element x to the back of queue. */
public void push(int x) {
while (!s2.isEmpty()) {
s1.push(s2.pop());
}
s1.push(x);
}
/** Removes the element from in front of queue and returns that element. */
public int pop() {
while (!s1.isEmpty()) {
s2.push(s1.pop());
}
return s2.pop();
}
/** Get the front element. */
public int peek() {
while(!s1.isEmpty()) {
s2.push(s1.pop());
}
return s2.peek();
}
/** Returns whether the queue is empty. */
public boolean empty() {
return s1.isEmpty() && s2.isEmpty();
}
}
/**
* Your MyQueue object will be instantiated and called as such:
* MyQueue obj = new MyQueue();
* obj.push(x);
* int param_2 = obj.pop();
* int param_3 = obj.peek();
* boolean param_4 = obj.empty();
*/