GuilinDev

Lc0334

05 August 2008

334. Increasing Triplet Subsequence

给定一个整数数组 nums,如果存在三个索引 (i, j, k) 使得 i < j < k 且 nums[i] < nums[j] < nums[k],则返回 true。如果不存在这样的索引,则返回 false。

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Example 1:

Input: nums = [1,2,3,4,5]
Output: true
Explanation: Any triplet where i < j < k is valid.

Example 2:

Input: nums = [5,4,3,2,1]
Output: false
Explanation: No triplet exists.

Example 3:

Input: nums = [2,1,5,0,4,6]
Output: true
Explanation: The triplet (3, 4, 5) is valid because nums[3] == 0 < nums[4] == 4 < nums[5] == 6.
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class Solution {
    public boolean increasingTriplet(int[] nums) {
        int first=Integer.MAX_VALUE, second=Integer.MAX_VALUE;
        for(int n : nums){
            if(n <= first) //found first 
                first = n;
            else if(n <= second)//found second bigger than first
                second = n;
            else //found third , bigger than first and second
                return true;
        }
        return false; //did not find triplet
    }
}