GuilinDev

Lc0341

05 August 2008

341 - Flatten Nested List Iterator

原题概述

Given a nested list of integers, implement an iterator to flatten it.

Each element is either an integer, or a list – whose elements may also be integers or other lists.

Example 1:
Given the list

1
[[1,1],2,[1,1]]
,

By calling next repeatedly until hasNext returns false, the order of elements returned by next should be:

1
[1,1,2,1,1]
.

Example 2:
Given the list

1
[1,[4,[6]]]
,

By calling next repeatedly until hasNext returns false, the order of elements returned by next should be:

1
[1,4,6]
.

题意和分析

建立压平嵌套链表的迭代器,而迭代器一般都是用迭代的方法来解,如果要用递归一般都需用栈来辅助遍历,由于栈的后进先出的特性,在对向量遍历的时候,从后往前把对象压入栈中,那么第一个对象最后压入栈就会第一个取出来处理,我们的hasNext()函数需要遍历栈,并进行处理,如果栈顶元素是整数,直接返回true,如果不是,那么移除栈顶元素,并开始遍历这个取出的list,还是从后往前压入栈,循环停止条件是栈为空,返回false。

代码

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/**
 * // This is the interface that allows for creating nested lists.
 * // You should not implement it, or speculate about its implementation
 * public interface NestedInteger {
 *
 *     // @return true if this NestedInteger holds a single integer, rather than a nested list.
 *     public boolean isInteger();
 *
 *     // @return the single integer that this NestedInteger holds, if it holds a single integer
 *     // Return null if this NestedInteger holds a nested list
 *     public Integer getInteger();
 *
 *     // @return the nested list that this NestedInteger holds, if it holds a nested list
 *     // Return null if this NestedInteger holds a single integer
 *     public List<NestedInteger> getList();
 * }
 */
public class NestedIterator implements Iterator<Integer> {
    
    Stack<NestedInteger> stack = new Stack<>();

    public NestedIterator(List<NestedInteger> nestedList) {
        //构造器先把所有NestedIterator的对象从后向前加入到栈中
        for (int i = nestedList.size() - 1; i >= 0; i--) {
            stack.push(nestedList.get(i));
        }
    }

    @Override
    public Integer next() {
        // 返回stack顶部元素的整数
        return stack.pop().getInteger();
    }

    @Override
    public boolean hasNext() {
        while (!stack.isEmpty()) {
            NestedInteger ni = stack.peek();
            if (ni.isInteger()) { // 如果时数字,返回
                return true;
            }
            stack.pop(); // 否则是数组,嵌套从尾到头压入栈
            for (int i = ni.getList().size() - 1; i >= 0; i--) {
                stack.push(ni.getList().get(i));
            }
        }
        return false;
    }
}

/**
 * Your NestedIterator object will be instantiated and called as such:
 * NestedIterator i = new NestedIterator(nestedList);
 * while (i.hasNext()) v[f()] = i.next();
 */