05 August 2008
”#”代表后退键，判断两个string是否相同
Stack
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class Solution {
public boolean backspaceCompare(String S, String T) {
return compute(S).equals(compute(T));
}
private Stack<Character> compute(String S) {
Stack<Character> stack = new Stack();
for (char c : S.toCharArray()) {
if (c != '#') {
stack.push(c);
} else if (!stack.isEmpty()) {
stack.pop();
}
}
return stack;
}
}
另外解法
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class Solution {
private String getString(String str) {
int n=str.length(), count=0;
String result="";
for(int i=n-1; i>=0; i--) {
char ch=str.charAt(i);
if(ch=='#')
count++;
else {
if(count>0)
count--;
else {
result+=ch;
}
}
}
return result;
}
public boolean backspaceCompare(String S, String T) {
return getString(S).equals(getString(T));
}
}