GuilinDev

Lc1351

05 August 2008

1351 Count Negative Numbers in a Sorted Matrix

行列均为非递增(降序),统计负数的总数量

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public int countNegatives(int[][] grid) {
    int rows = grid.length, cols = grid[0].length; 
    int res = 0, lastNeg = cols - 1;
    for (int row = 0; row < rows; row++) {
        //check edge cases - if first element is < 0 - all elements in row are negative
        if (grid[row][0] < 0) {
            res+=cols;
            continue;
        }
        //if last element is positive - it means there are no negative numbers in a row
        if (grid[row][cols - 1] > 0)
            continue;
        //there is a mix of negative and positive ones, need to find the border. starting
        //binary search
        int l = 0, r = lastNeg;
        while (l <= r) {
            int m = l + (r - l)/2;
            if (grid[row][m] < 0) {
                r = m - 1;
            } else
                l = m + 1;
        }
        //l points to the first negative element, which means cols - l is a number of
        //such elements
        res += (cols - l); lastNeg = l;
    }
    return res;
}